12(2x^2-11x-40)=0

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Solution for 12(2x^2-11x-40)=0 equation:


Simplifying
12(2x2 + -11x + -40) = 0

Reorder the terms:
12(-40 + -11x + 2x2) = 0
(-40 * 12 + -11x * 12 + 2x2 * 12) = 0
(-480 + -132x + 24x2) = 0

Solving
-480 + -132x + 24x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '12'.
12(-40 + -11x + 2x2) = 0

Factor a trinomial.
12((-5 + -2x)(8 + -1x)) = 0

Ignore the factor 12.

Subproblem 1

Set the factor '(-5 + -2x)' equal to zero and attempt to solve: Simplifying -5 + -2x = 0 Solving -5 + -2x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2x = 0 + 5 -2x = 0 + 5 Combine like terms: 0 + 5 = 5 -2x = 5 Divide each side by '-2'. x = -2.5 Simplifying x = -2.5

Subproblem 2

Set the factor '(8 + -1x)' equal to zero and attempt to solve: Simplifying 8 + -1x = 0 Solving 8 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1x = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1x = 0 + -8 -1x = 0 + -8 Combine like terms: 0 + -8 = -8 -1x = -8 Divide each side by '-1'. x = 8 Simplifying x = 8

Solution

x = {-2.5, 8}

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